# If A(-3,2) , (-1,4) and (4,-3) are three consecutive vertices of a parallelogram ABCD, then the coordinate of the fourth coordinate

Solution: We have,

$\\ A(-3,2),B(-1,4);and;C(4,-3)$  Let $D(h,k)$

Now,

Mid point of AC=Mid point of BD

$-3+4/2=-1+h/2\\ \\\Rightarrow h=2\\ \\\Rightarrow 2-3/2=4+k/2\\ \\\Rightarrow k=-5\\ \\ \Rightarrow D(h,k)=D(2,-5)$

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