If a-b and a+b and a are zeroes of polynomial 2x^3-6x^2+5x-7=0, find a

Answers (1)

in a cubic polynomial,

sum \ of \ roots=-\frac{coefficient \ of \ x^2}{coefficient \ of \ x^3}

i.e (a+b)+(a-b)+a=3a=-\frac{-6}{2}=\frac{6}{2}=3

So a=1

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