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If a,b,c are non-zero rational numbers such that a+b+c=0, then the roots of the equation (b+c-a)x^2+(c+a-b)x+(a+b-c)=0

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Solution:    As  a+b+c=0 ,  We can write the equation

                 2ax^2+2bx+2c=0    Rightarrow    ax^2+bx+c=0

           Note that x=1 satisfies this equation and its other root is c/a.

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Deependra Verma

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