If arg(z)<0, then arg(-z) -arg(z)=?

Answers (1)

Solution: Since  arg z< 0 , We choose arg z=-	heta

                	herefore    arg(-z)=-[pi -(-	heta )]=-pi-	heta =2pi+(-pi-	heta)

                     arg(-z)= pi+(-	heta)=pi+arg z

             Hence ,   arg(-z)-argz=pi

                

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