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If k35624 is divisible by 11, then what is the value of k? is it 6 or 5?

Answers (1)

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As we know

A number is divisible by 11 if the difference of the sum of digits in the odd places and the sum of digits in even places is either 0 or divisible by 11.

So for the number k35624

sum of digits in odd places = k+5+2 = k+7

and sum of digits in even places = 3+6+4 = 13

So Using

the difference of the sum of digits in the odd places and the sum of digits in even places=0

we get

 k+7 = 13

So k=6

And using 

the difference of the sum of digits in the odd places and the sum of digits in even places=11,22,33...

So K can take values like

K=6, (6+11), (6+22), (6+33)....

 

Posted by

avinash.dongre

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