As we know
A number is divisible by 11 if the difference of the sum of digits in the odd places and the sum of digits in even places is either 0 or divisible by 11.
So for the number k35624
sum of digits in odd places = k+5+2 = k+7
and sum of digits in even places = 3+6+4 = 13
So Using
the difference of the sum of digits in the odd places and the sum of digits in even places=0
we get
k+7 = 13
So k=6
And using
the difference of the sum of digits in the odd places and the sum of digits in even places=11,22,33...
So K can take values like
K=6, (6+11), (6+22), (6+33)....