If omega be a cube root of unity and (1+omega^2)^n=(1+omega^4)^n then the least +ve value of n is

Answers (1)

Solution:    We know that ,   1+omega +omega ^2=0 & omega ^3=1

          Now ,   (1+omega -omega ^2)^7=(-omega ^2-omega ^2)^7=(-2omega ^2)^7=-128omega ^2

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