# If one of the two slits of a Youngâ€™s double slit experiment is painted over so that it transmits half the light intensity of the other thenâ€‹

$\\ Case 1: \text{When slit are of equal width, if}\ I_{o} \ \text{is intensity of light then,}\\ I_{\max }=I_{o}+I_{o}+2 \sqrt{I_{o} I_{o}}=4 I_{o} \\ I_{\min }=I_{o}+I_{o}-2 \sqrt{I_{o} I_{o}}=0 \\ Case 2 : \text{When one of the slit is painted over, its intensity would reduce to half then,}\\ I_{\text {newmax}}=I_{o} / 2+I_{o}+2 \sqrt{I_{o} I_{o} / 2}=2.932 I_{o}\\ I_{\text {newmin}}=I_{o} / 2+I_{o}-2 \sqrt{I_{o} I_{o} / 2}=0.068 I_{o}\\ \text{Therefore, dark fringes get brighter and bright fringes get darker}$

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