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  • If sum of the square of zeros of the quadratic polynomial f(x) =x^2-8x+k is 40, find the value of k

If sum of the square of zeros of the quadratic polynomial f(x) =x^2-8x+k is 40, find the value of k

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Solution: Let \alpha ,eta be the zeros of the polynomial \ f(x)=x^2-8x+k Then,

\(alpha +eta )=8 And \alpha eta =k

It is given that

\alpha ^2+eta ^2=40\ \Rightarrow (alpha +eta )^2-2alpha eta =40\ \Rightarrow 64-2k=40\ \Rightarrow 2k=24\ \Rightarrow k=12

Posted by

Deependra Verma

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