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If the Earth is at one fourth of its present distance from the Sun, the duration of the year will be (a) one fourth of the present year (b) half the present year (c) one eighth the present year (d) one sixth the present year

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By Kepler's law 

\\T^2\propto R^3\\\\\frac{T_1}{T_2}=(\frac{R}{\frac{R}{4}})^\frac{3}{2}=8\\\\T_2=\frac{T_1}{8}

That is on - eighth the present year

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Safeer PP

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