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If the ratio of the roots of the equation ax^2+bx+c=0 be p:q then (A) pqb^2+(p+q)^2ac=0(B)pqb^2-(p+q)^2ac=0 (C) pqa^2-(p+q)^2bc=0 (D) None

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Solution: Given ,     ax^2+bx+c=0   and alpha :eta =(p/q)

                   \Rightarrow      alpha +eta =-(b/a) and  alpha cdot eta =c/a

         Now ,           alpha +(q/p)alpha =-(b/a)Rightarrow alpha [1+q/p]=-(b/a)

      Hence,          alpha cdot eta =(q/p)alpha ^2=c/a  

 

         

Posted by

Deependra Verma

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