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In fig 5 , a tent is in the shape of a cylinder surmounted by a conical top of the same diameter. If the height and diameter of the cylinder part are 2.1 m and 3 m respectively and the slant height of the conical part is 2.8, find the cost of canvas needed to make the tent if the canvas is available at the rate of  500/sq.meter 

 

 

 

 
 
 
 
 

Answers (1)

radius r = 3/2 = 1.5 m 

slant height of conical part l = 2.8 m 

height of cylindrical part H = 2.1 m 

surface area of tent = CSA of cone + CSA of cylinder 

\pi r l + 2 \pi r h \\\\ \pi r ( l+2h ) \\\\ = 22/7 \times 1.5 ( 2.8 + 2 \times 2. 1) \\\\ = 22/7 \times 1.5 \times ( 2.8 +4.2 ) = 22/7 \times 1.5 \times = 33 m^2

cost of 1 m^2 = 500 

cost of 33 m^2 = 500 * 33 = Rs 16500 

Posted by

Ravindra Pindel

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