Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • In Figure-2, PQ is tangent to the circle with centre at O, at the point B. If  , then <img alt=

In Figure-2, PQ is tangent to the circle with centre at O, at the point B. If \angle AOB = 100^{\circ} , then \angle ABP is equal to 
Option: 1 50°
Option: 2 40°
Option: 3 60°
Option: 4 80°

Answers (1)

\\ $ In triangle AOB $ \\ OA = OB \\ \therefore \angle OAB = \angle OBA \\ \angle OAB + \angle OBA + \angle AOB = 180^0 \\ \angle OBA + \angle OBA + \angle AOB = 180^0\\ 2 \angle OBA + 100^0 = 180^0 \\ \angle OBA = 40^0 \\ \angle OBP = 90^0 \\ \angle OBA + \angle ABP = 90^0 \\ 40^0 + \angle ABP = 90^0 \\ \angle ABP = 50^0 \\

Posted by

Safeer PP

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10 board exams twice a year ‘relief’ or ‘burden’? Parents, schools share mixed views
anam-khan

CBSE Class 10 exams twice a year from 2026; 64.4% students in favor, second attempt optional

Latest Question