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  • In Figure-2, PQ is tangent to the circle with centre at O, at the point B. If  , then <img alt=

In Figure-2, PQ is tangent to the circle with centre at O, at the point B. If \angle AOB = 100^{\circ} , then \angle ABP is equal to 
Option: 1 50°
Option: 2 40°
Option: 3 60°
Option: 4 80°

Answers (1)

\\ $ In triangle AOB $ \\ OA = OB \\ \therefore \angle OAB = \angle OBA \\ \angle OAB + \angle OBA + \angle AOB = 180^0 \\ \angle OBA + \angle OBA + \angle AOB = 180^0\\ 2 \angle OBA + 100^0 = 180^0 \\ \angle OBA = 40^0 \\ \angle OBP = 90^0 \\ \angle OBA + \angle ABP = 90^0 \\ 40^0 + \angle ABP = 90^0 \\ \angle ABP = 50^0 \\

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