# Mention the number of sodium and chloride ions in each unit cell of NaCl

Since there are 8 chloride ions at 8 corners of a cube and 6 chloride ions at 6 face centres, thus the total number of chloride ions in a unit cell:

$\mathrm{8\: \times \: \frac{1}{8}\: +\: 6\: \times\: \frac{1}{2}\:=\: 1\: +\: 3\: =\: 4}$

Again, there are 12 sodium ions on the edges and one in the centre of the unit cell. Thus, total number of sodium ions in the unit cell:

$\mathrm{12\: \times \: \frac{1}{4}\: +\: 1\: \times\: \frac{1}{1}\:=\: 3\: +\: 1\: =\: 4}$

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