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  • Plz answer this question friends? cot ^2 x [( secx - 1) / ( 1 + sinx) ] + sec^2x [ ( sinx - 1 )/ (1 + secx ) ]

Plz answer this question friends?

cot ^2 x [( secx - 1) / ( 1 + sinx) ] + sec^2x [ ( sinx - 1 )/ (1 + secx ) ]

Answers (1)

best_answer

Solution: We have ,

⇒  cot ^2 x [( secx - 1) / ( 1 + sinx) ] + sec^2x [ ( sinx - 1 )/ (1 + secx ) ]

 we know    ,  sin^2x + cos^2x = 1 and         1 + tan^2x = sec^2x 

⇒ [ cot^2x ( sec^2x - 1 )+ sec^2x ( sin^2x - 1) ] / (1 + sinx ) (1 +secx )

⇒  ( -1 - 1) /( 1+ sinx ) ( 1 + secx )

⇒   - 2 / ( 1 + sinx ) ( 1 + secx )

Posted by

Deependra Verma

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