(a+b)³+(a-b)³+6a(a²-b²) = a3+b3+3ab(a+b)+a3-b3-3ab(a-b)+6a(a+b)(a-b) =2a3+3a2b+3ab2-3a2b+3ab2+6a(a+b)(a-b) =2a3+6ab2+6a(a+b)(a-b) =2a3+6a(b2+a2-b2) =2a3+6a3 =8a3
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