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  • Sin2? . cos2? - cos2? . sin2? = sin2? - sin2?

Sin2? . cos2? - cos2? . sin2? = sin2? - sin2?

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best_answer

Given that

                    $$ sin^2A Cos^2B- Cos^2A Sin^2B = Sin^2A - Sin^2B

from the LHS 

                  $$ Sin^2A Cos^2B- Cos^2A Sin^2B $$\ $$= Sin^2 A (1 - Sin^2B) - (1- Sin^2A) Sin^2B$$\ $$= Sin^2A - Sin^2A . Sin^2B - Sin^2 B+ Sin^2A Sin^2B $$\ $$ = Sin^2A - Sin^2 B$$\ RHS

Hence, its proved LHS = RHS

        

Posted by

Deependra Verma

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