Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • State Bohr's quantization condition of angular momentum. Calculate the shortest wavelength of the Brackett series and state to which part of the electromagnetic spectrum does it belong.   &nb

State Bohr's quantization condition of angular momentum. Calculate the shortest wavelength of the Brackett series and state to which part of the electromagnetic spectrum does it belong.

 
 
 

Answers (1)

According to the Bohr's quantization condition:- The angular momentum of an electron in an orbit around the hydrogen atom has to be an integral multiple of plank's constant divided by 2 \pi

Mathematically it can be written as:-

L=\frac{nh}{2\pi }

For the Brackett series, the wavelength can be given by the formula :

\frac{1}{\lambda }=R\left ( \frac{1}{4^{2}}-\frac{1}{n^{2}} \right )

'n' has to be maximum for the wavelength to be shortest, that is n=\infty

Hence, 

\frac{1}{\lambda }=1.097\times 10^{7}m^{-1}\left ( \frac{1}{16}-0 \right )

\lambda =1.46\times 10^{-6}m

This wavelength (\lambda =1.46\times 10^{-6}m) belongs to the infrared part of the electromagnetic spectrum

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE admit card 2025 out for Class 10, 12 supplementary exams
anam-khan

CBSE Class 10, 12 practical exams 2025 for compartment students from July 10; detailed guidelines issued
anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in

Latest Question