Sum of 3 numbers in AP is 37 & their product is 405. Find the number

Answers (1)

Assume three numbers in AP are a-d, a, a+d.

ATQ

a -d +  a + a+d = 37

3a = 37

a = 37/3 = 12.333

a(a-d)(a+d) = 405

a(a2 -d2 ) = 405

12.33(152.11 -d2 ) = 405

d2 = 119.27

d = 10.92

Hence the numbers are 1.41, 12.33, 23.25.

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