The age of a father is 3 years more than three times the age of his son. Three years later the father's age will exceed twice the age of his son by 13 years. What will be their ages after 4 years?

Answers (1)

Let the present age of son be x.
So the present age of father = 3x + 3                
After 3 years,

age of son = x+3

and Age of father=3x+3+3  ....(1)

but According to the question
the Age of father after 3 years = 2(x+3) + 13 .....(2)
comparing equation  (1) and (2)
3x + 3 +3 = 2(x+3) + 13
3x + 6 = 2x + 19
x = 13
So, Father's present age = 3x + 3 = 42
Age of son after 4 years = 13 + 4 = 17
Age of father after 4 years = 42 + 4 = 46

 

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