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  • The angles of pentagon are x,[x+20],[x+40],(x+60),[x+80] thenfind the smallest angle.

The angles of pentagon are x,[x+20],[x+40],(x+60),[x+80] thenfind the smallest angle.

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The sum of the interior angles of a pentagon is 540

So

x+x+20+x+40+x+60+x+80=540
5x+200=540
5x=340
x=68

Therefore the smallest angle of the pentagon = x = 68

Posted by

avinash.dongre

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