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  • The digit at the tens place of a two digit number is three times the digit at the ones place.if the sum of the number and the number formed by reversing the digits is 88 find the number

The digit at the tens place of a two digit number is three times the digit at the ones place.if the sum of the number and the number formed by reversing the digits is 88 find the number

Answers (1)

best_answer

 let the digit in the tens place be x and digit in the one's place be y.  

So according to the question

x=3y .....(1)

And the original number = 10x+y

and the new number when digits are interchanges=10y+x

So according to the question

(10x+y)+(10y+x) = 88  

11x+11y=88

x+y=8  ...(2)

Putting equation (1) in the equation (2) we get

3y+y=8

4y=8

y=2

so

x=3*y=3*2=6

So the the original number = 10x+y=(10*6)+2=62

Posted by

avinash.dongre

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