# The equation of the directix of the parabola y^2+4y+4x+2=0 is

Solution: we have the given equation $\\ y^2+4y+4x+2=0$

The given equation can be written as

$\\ (y+2)^2=-4(x-1/2)$

Form $\\ Y^2=4AX; where ; 4A=-4\Rightarrow A=-1$

The directrix is $\\ X=-A; or; (x-1/2)=-(-1)\\ \\\Rightarrow x=3/2$

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