The equation of the line perpendicular to x+3y=7

Answers (1)

Given Line x+3y=7

x+3y=7; written in the slope intercept form will be

y= -(1/3)x + (7/3) where the slope will be -1/3 then the slope of the perpendicular line to this line will be 3.

as m1m2=-1

writing the new equation in the point slope form we have

(y-1) = 3(x-0)

the equation will be:

y = 3x + 1

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