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The equation of the normal the curve parametrically represented by x= t^2+3t-8 and y=2t^2-2t-5 at the point P(2,-1) is

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Solution:  We have ,   

                   x=t^2+3t-8,y=2t^2-2t-5

               \ \ Rightarrow x=t^2+3t-8=2Rightarrow t=2,-5.\ \ Rightarrow y=2t^2-2t-5=-1Rightarrow t=2,-1.

             	herefore t=2,fracmathrmd ymathrmd x=frac4t-22t+3Rightarrow fracmathrmd ymathrmd x=frac67

           	herefore        Equation of normal     (y+1)=-frac76(x-2)

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Deependra Verma

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