The focal distance of a point on a parabola y^2=8x. is find it.

Answers (1)

Solution: Comparing  \ y^2=8x   With  \ y^2=4ax

    	herefore 4a=8Rightarrow a=2 

	herefore Equation of directrix is  \x+2=0

Let \(alpha ,eta ) on the parabola 

\Rightarrow y^2=8x\ \	herefore eta ^2=8alpha \ \ecause SP=8\ \ Rightarrow PM=8Rightarrow alpha +2=8\ \Rightarrow alpha =6Ans

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