# The integral value of m for which the Quadratic equation (x+m)(x-5)+1=0 has integral roots ,are

Solution: The given equation can be written as:

$\\ x^2+(m-5)x+(1-5m)=0 ........(1)\\ \\ \Rightarrow D=0$

gives $\\ m=-3 ; and; m=-7$

Now, $\\ x=1/2\times (5-m)$

for     m=-3 ,x=4

for m=-7 , x=6

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