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  • The line joining the complex number (1+i square root 3) with origin is rotated about the origin through an angle of pi/6 in anti-clockwise direction then the new position of the point is .

The line joining the complex number (1+i square root 3) with origin is rotated about the origin through an angle of pi/6 in anti-clockwise direction then the new position of the point is .

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Solution: 1+isqrt3=2(cospi /3+isinpi /3)

       After rotation , the new argument =pi /3+pi /6=pi /2

    herefore The new position of the complex number

       \ =2(cospi /2+isinpi /2)=2i.

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Deependra Verma

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