The mean deviation of the numbers 1, 2, 3, 4, 5 is

Answers (1)

The given distribution is 1,2,3,4,5
Here the total number of terms is N=5
And the middle term(Medium)is overlinex=3
	herefore Mean deviation is fracsumleft | x-overlinex 
ight | N
Rightarrow frac2+1+0+1+25=1.2

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