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The multiplicative inverse of (1+i/1-i) is

Answers (2)

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Solution: We have ,

$z=(1+i/1-i)Rightarrow z^-1=(1-i/1+i)=1/2(1-i)^2=-i$

Posted by

Deependra Verma

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1/1+i ×1-i/1-i

=1-i/1×1+i×i

=1-i/2

=1/2 - i/2 in the form of a+ib

Posted by

Harsha

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