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The number of irrational roots of the equation ( x-1)(x-2)(3x-2)(3x+1)=21 is

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Solution:      (3x-2)(x-1)(3x+1)(x-2)=21

                    (3x^2-5x+2)(3x^2-5x-2)=21\ \Rightarrow (3x^2-5x^2)-4=21Rightarrow 3x^2-5x=pm 5\ \Rightarrow 3x^2-5x-5=0hspace0.2cmorhspace0.2cm3x^2-5x+5=0

                    The first equation has  irrational roots and the

                    second has imaginary roots.

 

                

Posted by

Deependra Verma

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