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  • The number of real roots of (x-1/x+1)^4-13(x-1/x+1)^2+36=0 is

The number of real roots of (x-1/x+1)^4-13(x-1/x+1)^2+36=0 is

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Solution:   Put  (x-1/x+1)^2=y to obtain

               y^2-13y+36=0Rightarrow y=4,9

              herefore    (x-1/x+1)=pm 2,pm 3

           Thus the given equation has four real roots.

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Deependra Verma

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