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Get Answers to all your Questions
The number of unit cells present in 58.5g of NaCl is​
Answers (1)
We know
molar mass of NaCl = 58.5
moles = mass/molar mass
= 58.5 / 58.5 = 1 mol
According to Avagadro's constant, 1 mole of any substance = 6.022 × 1023 molecules/atoms/unit cells.
in bcc, each unit cell contains 4 molecules of NaCl
so, The number of unit cells present in 58.5g of NaCl is​
= 6.022 x 1023/4
= 1.5 x 1023
View full answer
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