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The percentage error in the measurement oftime period “T” and length "L" of a simplependulum are 0.2 % and 2% respectively, themaximum % age error in LT2 is:(a) 0.4 %(b) 2.2 %(c) 1.8 %(d) 2.4 %​

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Here Q=LT^2

and \frac{\Delta L}{L}*100=2 and \frac{\Delta T}{T}*100=0.2

So \frac{\Delta Q}{Q}*100=\frac{\Delta L}{L}*100+2\frac{\Delta T}{T}*100=2+2*(0.2)=2.4

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avinash.dongre

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