The period of oscillation for a simple pendulum is measured in the successive oscillations are 2.63 s,2.56 s,2.92 s,2.71 s,2.80 s.calculate true value, mean absolute error ?

Answers (1)

So true value=2.72 s

\\ \text{The absolute error can be calculated as}, \\ \text{For first reading},\\ \begin{array}{l} \Delta x_{1}=|2.63-2.72| \\ \Delta x_{1}=0.09 \mathrm{s} \end{array} \\ \text{For second reading}, \\ \Delta x_{2}=|2.56-2.72| \\ \Delta x_{2}=0.16 \mathrm{s} \\ \text{For third reading}, \\ \begin{array}{l} \Delta x_{3}=|2.92-2.72| \\ \Delta x_{3}=0.20 \mathrm{s} \end{array} \\ \text{For forth reading}, \\ \Delta x_{4}=|2.71-2.72| \\ \Delta x_{4}=0.01 \mathrm{s} \\ \text{For fifth reading}, \\ \begin{array}{l} \Delta x_{5}=|2.80-2.72| \\ \Delta x_{5}=0.08 \mathrm{s} \end{array}

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