# The ratio of the angular speeds of the hour hand and the minute hand of a clock is

$\begin{array}{l} \text { Time period of minute hand } \\ T_{1}=1 h r \\ T_{1} m_{2} \text { Time period ofhour hand } \\ T_{2}=12 \mathrm{hr} \end{array}$

$\begin{array}{l} \omega_{\min }=\frac{2 \pi}{1} \frac{r a d}{hr } \text { and } \omega_{h r}=\frac{2 \pi}{12} \frac{R a d}{hr} \\ \frac{\omega_{\min }}{\omega_{h r}}=\frac{\frac{2 \pi}{1}}{\frac{2 \pi}{12 }}=12:1 \end{array}$

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