# The sides AB, BC, CD and DA of a quadrilateral have theequations x + 2y = 3, x= 1, x-3y = 4 and 5x + y + 12 = 0respectively. Find the angle between the diagonals AC andBD.â€‹

$\\ \text{Slope of AC}\\ m_{1}=\frac{-1-3}{1-(-3)}=-1 \\ \text{Slope of BD,}\\ m_{2}=\frac{-2-1}{-2-1}=1 \\ \because m_{1} \times m_{2}=-1 \\ \therefore angle between diagonal =90^{\circ}$

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