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The Sum to infinity of the series 1+4/5 +7/5^2+10/5^3+...... is

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Solution:  

           S=1+4/5+7/5^2+10/5^3+....hspace1cm.....(1)

                   (1/5)S=1/5+4/5^2+7/5^3+.....hspace1cm.......(2)

       Subtracting  (2)  from (1) , we get

       (4/5)S=1+3/5+3/5^2+3/5^3+.......=1+(3/5)/1-(1/5)=1+3/4=7/4

     Rightarrow           S=35/16  

Posted by

Deependra Verma

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