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  • The value of alpha for which the system of equation x+y+z=1 , x+2y+4z=(alpha)x+4y+10z=(alpha)^2 is consistent, are given by

The value of alpha for which the system of equation x+y+z=1 , x+2y+4z=(alpha)x+4y+10z=(alpha)^2 is consistent, are given by

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Solution:   Subtracting first equation from the second and

                  third , we get

                  y+3z=alpha -1

               3y+9z=alpha ^2-1

      herefore      alpha ^2-1=3(alpha -1)   Rightarrow   alpha =1 or alpha =2

Posted by

Deependra Verma

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