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Thee perimeter of a triangle is 288 m and ratio of side is 3:4:5. find the area of the triangle

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Let a,b,c be the sides of the triangle

and a+b+c = 288 meters 

and   a:b:c = 3:4:5  

And the traigle is Right angle triangle where c is hypotenous

If a=3x then b=4x and c=5x

So a+b+c = 288

3x+4x+5x=288

12x=288

x=24

Now area of triagle is given as

 A=\frac{1}{2}a*b=\frac{1}{2}*3x*4x=6x^2=6*24*24=3456 \ m^2

Posted by

avinash.dongre

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