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Two forces of 30 N and 40 n are inclined to each other at an angle of 60 degree.Find the resultant

Answers (1)

R² = P² + Q² + 2 P Q cos Ф= 30² + 40² + 2x 30x 40 xcos 60= 900 + 1600 + 2400 * 1/2 = 3700
So, R = 10 √37 Newtons

Angle of  the resultant force with 30 N force is
     tan α = Q sin Ф  /  (P + Q cos Ф)
             = 40 (√3 / 2)/ (30+(40*1/2))  = 2√3 / 5
     α =  tan-1 (2√3/5) = 34.7 degrees

Posted by

shubham.krishnan

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