Two forces whose magnitudes are in ratio 3:5 give a resultant equal to 49N, if the angle of inclination is 60 degree, find the magnitude of each force

Answers (1)

Let the two forces are p and q then 
p/q = 3/5
according to question 

49=\sqrt{p^2+q^2+2pqcos60}=\sqrt{p^2+q^2+pq}=\sqrt{\frac{9}{25}q^2+q^2+\frac{3}{5}q^2}\\\Rightarrow 49=\sqrt{\frac{49}{25}q^2}\\\Rightarrow 49 = 7q/5\\\Rightarrow q = 35N \ \ and \ \ p = 21N

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