Get Answers to all your Questions

header-bg qa

Two identical resistors, each of resistance 15\; \Omega, are connected in (i) series, and (ii) parallel, in turn to a battery of 6\; V. Calculate the ratio of the power consumed in the combination of resistors in each case.

 

 

Answers (1)

Total resistance in series is 30 ohm

I = V/ Rp = 6V/ 30 = 0.2 A

P1 = VI = 6V × 0.2 A = 1.2 W

Total resistance in parallel is 7.5 ohm

I = V/ Rp = 6V/ 7.5 = 0.8 A

P2 = VI = 6V * 0.8A = 4.8 W

Ratio of power = P1 / P2 = 1.2W / 4.8W = 1 : 4

 

Posted by

Safeer PP

View full answer