Two identical resistors, each of resistance , are connected in (i) series, and (ii) parallel, in turn to a battery of
. Calculate the ratio of the power consumed in the combination of resistors in each case.
Total resistance in series is 30 ohm
I = V/ Rp = 6V/ 30 = 0.2 A
P1 = VI = 6V × 0.2 A = 1.2 W
Total resistance in parallel is 7.5 ohm
I = V/ Rp = 6V/ 7.5 = 0.8 A
P2 = VI = 6V * 0.8A = 4.8 W
Ratio of power = P1 / P2 = 1.2W / 4.8W = 1 : 4