#### Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10

$Given:\;Two\;unbiased\;dice\;are\;thrown.\\*By\;using\;the\;formula,\\* P(E)=\frac{favourable\;outcomes}{total\;possible\;outcomes}\\*So,\;we\; now\;have\;to\;determine\;the\;probability\;of\;getting\;the\;sum\;of\\*digits\; on\;dice\;greater\;than\;10\\*Total\;number\;of\;possible\;outcomes\;is\; 6^2=36\\*\Rightarrow n(S)=36\\*Let\;E\;be\;the\;event\;of\;getting\;same\; number\;on\;all\;the\;three\;dice\\*\Rightarrow E=\left\{(5,6) (6,5) (6,6)\right\}\\*\Rightarrow n(E)=3\\*\Rightarrow P(E)=\frac{n(E)}{n(S)}\\* \Rightarrow \frac{3}{36}\\*\Rightarrow \frac{1}{12}$