Use Bohr’s model of hydrogen atom to obtain the relationship between the angular momentum and the magnetic moment of the revolving electron.

 

 
 
 
 
 

Answers (1)
S safeer

magnetic dipole moment, (\mu ) =IA                 

=\left ( \frac{e}{T} \right )\cdot \pi r^{2}= \frac{e}{\left ( \frac{2\pi r}{v} \right )}\cdot \pi r^{2} = \frac{evr}{2}

angular momentum of the electron L=mvr

\therefore \frac{\mu }{L} = \frac{evr}{2\cdot mvr} = \frac{e}{2m}

 

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