what is the maximum height for a ball after n collisions if it loses 3/4 of its energy after each collision when dropped from a height h to a floor

Answers (1)
S safeer

At first, ball is at height h and energy=mgh

After each collision 3/4 energy is lost. Which means 1/4 th of previous value is remaining after each collision,

After the first collision energy, E1 = mg (h/4) and ball rises to h/4

Next collision  the energy before the collision is E1 and after = E2= 1/4 E1
                        E2= 1/4[1/4 mgh] = (1/4)²  m g h 

After nth collision En= (1/4)n  m g h 

and height = (h/4)n

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