What is the molar volume of Nitrogen at 500 K and 600 atmospheric according to ideal gas law?

Answers (1)
S Sumit

Given 
Temperature(T) = 500 k
Pressure (P) = 600 atm
No. of moles (n) = 1
Now we have to find volume(V) = ?
According to Ideal gas equation 
PV = nRT

By substituting we get 
V = nRT/P
V = 1*0.0821*500/600 = 0.068417

 

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