What is the position of the element having outer electronic configuration (i) ns2np4 for n = 3 (ii) (n–1) d2ns2 for n = 4 ?

Answers (1)
S Sumit

 (i) For n=3, ns2np4 is 3s23p4

The complete electronic configuration is 1s2, 2s2 2p6, 3s23p4

Atomic number = 2 + 2 + 6  + 2 + 4 = 16

The element is sulphur in the 3rd period and in Group 16 (p-block)

 (ii) (n – 1)d2ns2 for n = 4 ; It is 3d24s2

The complete electronic configuration is

1s2,2s22p6,3s23p63d24s2

Atomic Number is 22, The element is Titanium

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