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What is the solution set of |2x + 1| > 5?A. x|1 < x < –3 B. x|–1 < x < 3 C. x|x > 2 or x < –3 D. x|x < 2 or x > –3

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Given expression

                            $$ |2x -1| > 5 $$

Squaring both sides, 

                                    $$ 4x^2 -4x +1 > 25 $$\$$ $$ 4x^2 -4x -24>0 $$\$$ $$x^2 - x - 6 > 0$$\$$ $$ (x - 3)(x+2)> 0 $$\$$

this is representing on the number line, 

                                                             $$Rightarrow x< -2 or x> 3 $$

Hence,  

                                              $$x<-2 or x> 3 $$ is correct 

Posted by

Deependra Verma

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