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Where should an object be placed in front of a concave mirror of focal length $20\; cm$ so as to obtain a two times magnified virtual image of the object ?

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Concave Mirror

Foacal length $=-20\; cm$
two times magnified virtual image $(m)=+2$ (image is virtual)

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\; \; \;\; \; m=\frac{-v}{u}=+2$

$\frac{-1}{24}+\frac{1}{4}=\frac{-1}{20}\; \; \; \; \; v=-24$

$u=-10\; cm$

object must be placed $10\; cm$ in front of mirror.

Posted by

Sumit Saini

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