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  • The octahedral complex  exists in two iso

The octahedral complex \mathrm{CoSO_{4}Cl\cdot 5NH_{3}} exists in two isomeric forms \mathrm{x} and \mathrm{y} . Isomer \mathrm{x} reacts with \mathrm{AgNO_{3}} to give a while precipitate,but does not react with \mathrm{BaCl_{2}} . Isomer \mathrm{y} gives white precipitate with \mathrm{BaCl_{2}} but does not react with \mathrm{AgNO_{3}}.

Isomers \mathrm{x} and \mathrm{y} are

Option: 1

ionization isomers


Option: 2

linkage isomers


Option: 3

co-ordination isomers


Option: 4

solvate isomers


Answers (1)

best_answer

Ionization isomers have the same central metal ion; only the ligands exchange place with anion or neutral ion outside of the co-ordination complex. The sole difference between the two isomers is which ligands are attached to the central metal.

The X isomer of \mathrm{CoS{{O}_{4}}Cl\cdot 5\text{ N}{{\text{H}}_{3}}} is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl}and the Y isomer is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}}

Their reactions are as follows:

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl\text{ }\left( X \right)\text{ }\xrightarrow{AgN{{O}_{3}}}AgCl\downarrow \text{ (white ppt}\text{.)}}

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}\text{ (Y) }\xrightarrow{BaC{{l}_{2}}}BaS{{O}_{4}}\downarrow \text{ (white ppt}\text{.)}}

The correct answer is Option A- Ionization isomers.

Posted by

Gautam harsolia

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